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fix signed overflows at most-negative values in ato(i|l|ll)

patch by Pascal Cuoq (with minor tweaks to comments)
rs-1.0
Rich Felker 15 years ago
parent
commit
0c4188f6d7
  1. 5
      src/stdlib/atoi.c
  2. 5
      src/stdlib/atol.c
  3. 5
      src/stdlib/atoll.c

5
src/stdlib/atoi.c

@ -9,7 +9,8 @@ int atoi(const char *s)
case '-': neg=1;
case '+': s++;
}
/* Compute n as a negative number to avoid overflow on INT_MIN */
while (isdigit(*s))
n = 10*n + *s++ - '0';
return neg ? -n : n;
n = 10*n - (*s++ - '0');
return neg ? n : -n;
}

5
src/stdlib/atol.c

@ -10,7 +10,8 @@ long atol(const char *s)
case '-': neg=1;
case '+': s++;
}
/* Compute n as a negative number to avoid overflow on LONG_MIN */
while (isdigit(*s))
n = 10*n + *s++ - '0';
return neg ? -n : n;
n = 10*n - (*s++ - '0');
return neg ? n : -n;
}

5
src/stdlib/atoll.c

@ -10,7 +10,8 @@ long long atoll(const char *s)
case '-': neg=1;
case '+': s++;
}
/* Compute n as a negative number to avoid overflow on LLONG_MIN */
while (isdigit(*s))
n = 10*n + *s++ - '0';
return neg ? -n : n;
n = 10*n - (*s++ - '0');
return neg ? n : -n;
}

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